x^2-224=1.999x

Solution for x^2-224=1.999x equation:

x^2-224=1.999x

We move all terms to the left:

x^2-224-(1.999x)=0

We add all the numbers together, and all the variables

x^2-(+1.999x)-224=0

We get rid of parentheses

x^2-1.999x-224=0

a = 1; b = -1.999; c = -224;
Δ = b2-4ac
Δ = -1.9992-4·1·(-224)
Δ = 899.996001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.999)-\sqrt{899.996001}}{2*1}=\frac{1.999-\sqrt{899.996001}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.999)+\sqrt{899.996001}}{2*1}=\frac{1.999+\sqrt{899.996001}}{2}
$